Seymour, a city located in the state of Indiana (IN), is home to a population of approximately 21,373 people. Seymour boasts a median age of 34.5, with around 19.7% of its residents aged 60 or above. 6.3% of the population identifies as US Veterans. 13.6% of Seymour residents are disabled. The city has an average household income of $57,347, while the unemployment rate stands at 2.1%, and around 16.7% of the population is considered to be living below the poverty level. In terms of housing, the average home value in Seymour is $136,894, with a monthly rent averaging $905.
