About Selinsgrove, Pennsylvania
Selinsgrove, a city located in the state of Pennsylvania (PA), is home to a population of approximately 5,710 people. Selinsgrove boasts a median age of 24, with around 22.6% of its residents aged 60 or above. 3.4% of the population identifies as US Veterans. 15.7% of Selinsgrove residents are disabled. The city has an average household income of $56,295, while the unemployment rate stands at 1.5%, and around 6.2% of the population is considered to be living below the poverty level. In terms of housing, the average home value in Selinsgrove is $192,881, with a monthly rent averaging $910.