About Seymour, Wisconsin
Seymour, a city located in the state of Wisconsin (WI), is home to a population of approximately 3,534 people. Seymour boasts a median age of 35.7, with around 21.4% of its residents aged 60 or above. 3.7% of the population identifies as US Veterans. 6.6% of Seymour residents are disabled. The city has an average household income of $71,074, while the unemployment rate stands at 3.8%, and around 6.5% of the population is considered to be living below the poverty level. In terms of housing, the average home value in Seymour is $160,243, with a monthly rent averaging $837.